DIFFERENTIAL EQUATIONS 05

Autonomous Differential Equations

An autonomous differential equation gives the rate of change from the current state without explicit dependence on time.

The main idea

\[\boxed{\frac{dy}{dt}=f(y)}\]

The current value of \(y\) determines the current rate.

1. Equilibria

Equilibria satisfy \(f(y)=0\). At such a state, \(dy/dt=0\), so a solution starting there remains there.

2. Direction of movement

If \(f(y)\gt0\), then \(y\) increases. If \(f(y)\lt0\), then \(y\) decreases.

3. Logistic example

For

\[y'=y(1-y),\]

the equilibria are \(y=0\) and \(y=1\). For \(y\lt0\), the derivative is negative; for \(0\lt y\lt1\), it is positive; for \(y\gt1\), it is negative.

4. Stability

The sign pattern shows that \(y=1\) attracts nearby solutions, while \(y=0\) repels them.

5. Derivative test

If \(f'(y^*)\lt0\), an equilibrium is typically locally asymptotically stable. If \(f'(y^*)\gt0\), it is unstable.

6. Logistic population model

\[\frac{dP}{dt}=rP\left(1-\frac{P}{K}\right),\qquad r\gt0,\quad K\gt0.\]

For \(0\lt P\lt K\), population increases; for \(P\gt K\), it decreases. Thus \(K\) is a stable equilibrium.

7. Separation warning

Before dividing by \(f(y)\), first identify values where \(f(y)=0\), because these are equilibrium solutions and division by zero would remove them.

8. Practical method

\[\boxed{y'=f(y)\rightarrow f(y)=0\rightarrow\text{sign analysis}\rightarrow\text{phase line}\rightarrow\text{stability}}\]